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Qualifications · Teacher Employment Exam: Pedagogy & General Knowledge Lab

General Education 2: Numerical Reasoning, Logical Reasoning and Data Interpretation

Read the questions and explanations in English. The lectures (explanatory articles) are available in Japanese only.

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Q1 | Finding a percentage

52 people joined a course with a capacity of 80. What percentage of the capacity joined?

  1. 52%
  2. 65%
  3. 60%
  4. 70%
AnswerB. 65%

Percentage = compared amount ÷ base amount = 52 ÷ 80 = 0.65 = 65%. 52% just turns the head count into a percentage; 60% and 70% are miscalculations.

Q2 | Successive increase and decrease

A school had 400 pupils last year. This year the number rose by 10%, and next year it is expected to fall by 10% from this year. How many pupils are expected next year?

  1. 400
  2. 404
  3. 360
  4. 396
AnswerD. 396

This year: 400 × 1.1 = 440; next year: 440 × 0.9 = 396. The second 10% is taken from 440, so it does not return to 400. 404 underestimates the decrease, and 360 takes 10% off 400 directly.

Q3 | Finding the base amount

An item bought at 30% off the list price cost 2,100 yen. What is the list price?

  1. 3,000 yen
  2. 2,730 yen
  3. 2,800 yen
  4. 3,150 yen
AnswerA. 3,000 yen

A 30% discount means paying 0.7 of the list price, so list price = 2,100 ÷ 0.7 = 3,000 yen. 2,730 yen comes from 2,100 × 1.3, using the wrong base; 2,800 and 3,150 yen are miscalculations.

Q4 | Profit and loss

A shop priced an item costing 1,000 yen to make a 40% profit on cost. It did not sell, so the shop sold it at 20% off the list price. What was the profit?

  1. 200 yen
  2. 400 yen
  3. 80 yen
  4. 120 yen
AnswerD. 120 yen

List price = 1,000 × 1.4 = 1,400 yen; selling price = 1,400 × 0.8 = 1,120 yen; profit = 120 yen. 200 yen wrongly subtracts 40% − 20%; 400 yen forgets the discount; 80 yen is a miscalculation.

Q5 | Ratio and equations

The money held by an older and a younger sister is in the ratio 5:3. If the older sister gives 600 yen to the younger one, they have equal amounts. How much did the older sister have at first?

  1. 2,400 yen
  2. 3,000 yen
  3. 3,600 yen
  4. 1,800 yen
AnswerB. 3,000 yen

Let the amounts be 5x and 3x. Then 5x − 600 = 3x + 600, so x = 600 and the older sister had 3,000 yen (the younger had 1,800 yen). 1,800 yen is the younger sister’s amount; 2,400 and 3,600 yen come from wrong equations.

Q6 | Concentration (adding water)

100 g of water is added to 300 g of 8% salt water. What is the concentration of the new solution?

  1. 5%
  2. 7%
  3. 6%
  4. 4%
AnswerC. 6%

The salt is 300 × 0.08 = 24 g and does not change when water is added. The total is 400 g, so 24 ÷ 400 = 6%. 5%, 7% and 4% mix up the amount of salt or the total weight.

Q7 | Concentration (mixing)

200 g of 10% salt water is mixed with 100 g of 4% salt water. What is the concentration of the mixture?

  1. 7%
  2. 6%
  3. 9%
  4. 8%
AnswerD. 8%

Salt = 200 × 0.1 + 100 × 0.04 = 24 g; total = 300 g; 24 ÷ 300 = 8%. 7% averages 10 and 4 without weighting by amount; 6% and 9% are miscalculations.

Q8 | A percentage of a percentage

Of 600 students, 40% cycle to school, and 25% of the cyclists are first-years. How many first-year cyclists are there?

  1. 150
  2. 90
  3. 240
  4. 60
AnswerD. 60

Cyclists = 600 × 0.4 = 240; first-years among them = 240 × 0.25 = 60. 150 uses the whole school as the base, 240 is all cyclists, and 90 is a miscalculation.

Q9 | Raising then lowering a price

A price is raised by 20% and then lowered by 20% from the new price. The final price is what percentage of the original?

  1. 96%
  2. 100%
  3. 104%
  4. 80%
AnswerA. 96%

Multiply the factors: 1.2 × 0.8 = 0.96, i.e. 96%. The 20% cut is taken from the raised price, so it does not return to 100%. 104% gets the direction wrong, and 80% forgets the increase.

Q10 | Combined ratio

If A:B = 2:3 and B:C = 4:5, which is A:B:C?

  1. 2:3:5
  2. 2:7:5
  3. 6:9:10
  4. 8:12:15
AnswerD. 8:12:15

Make B the same using 12, the least common multiple of 3 and 4: A:B = 8:12 and B:C = 12:15, so A:B:C = 8:12:15. 2:3:5 does not match B; 2:7:5 adds 3 + 4; 6:9:10 does not fit B:C.

Q11 | Finding the whole from a percentage

15% of a number is 42. What is the number?

  1. 63
  2. 6.3
  3. 420
  4. 280
AnswerD. 280

Base = compared amount ÷ rate = 42 ÷ 0.15 = 280. 6.3 multiplies 42 by 0.15 by mistake; 63 and 420 also mishandle the rate.

Q12 | Concentration (adding salt)

How many grams of salt must be added to 240 g of 4% salt water to make 20% salt water?

  1. 38.4 g
  2. 48 g
  3. 40 g
  4. 60 g
AnswerB. 48 g

Let x g be added: 9.6 + x = 0.2 × (240 + x), so 0.8x = 38.4 and x = 48 g. 38.4 g forgets that the total weight also increases (240 × 0.2 − 9.6); 40 g and 60 g are miscalculations.

Q13 | Reaching a profit target

A shop buys 200 items at 80 yen each and sells them at 120 yen each. Unsold items are thrown away. At least how many must it sell to make a profit of 4,000 yen or more?

  1. 100
  2. 167
  3. 134
  4. 160
AnswerB. 167

Purchase cost = 80 × 200 = 16,000 yen. With n sold, 120n − 16,000 ≥ 4,000 gives n ≥ 166.6…, so at least 167. 100 comes from 4,000 ÷ (120 − 80), ignoring the cost of unsold items; 134 and 160 are not enough (160 gives only 3,200 yen).

Q14 | Distance

Someone travels at 12 km/h for 25 minutes. How far do they go?

  1. 3 km
  2. 5 km
  3. 4.8 km
  4. 6 km
AnswerB. 5 km

25 minutes = 25/60 hour, so 12 × 25/60 = 5 km. 3, 4.8 and 6 km come from converting minutes to hours incorrectly.

Q15 | Units of speed

Convert 5 metres per second into kilometres per hour.

  1. 18 km/h
  2. 0.3 km/h
  3. 30 km/h
  4. 3 km/h
AnswerA. 18 km/h

One hour is 3,600 seconds, so 5 × 3,600 = 18,000 m = 18 km. 0.3 km/h multiplies by 60 only once and mistakes 300 m (0.3 km) per minute for a speed per hour (300 m per minute = 18 km/h); 3 and 30 km/h are also conversion errors.

Q16 | Average speed for a round trip

Someone walks from home to a park at 6 km/h and back along the same road at 4 km/h. What is the average speed for the round trip?

  1. 4.8 km/h
  2. 5 km/h
  3. 5.2 km/h
  4. 4.5 km/h
AnswerA. 4.8 km/h

Take the one-way distance as 12 km: 2 hours there and 3 hours back, so 24 km ÷ 5 h = 4.8 km/h (the answer does not depend on the distance). 5 km/h averages 6 and 4, ignoring that the slower trip takes longer.

Q17 | Meeting problem

A and B start walking towards each other at the same time from two points 2.4 km apart. A walks at 70 m/min and B at 50 m/min. After how many minutes do they meet?

  1. 12 minutes
  2. 20 minutes
  3. 30 minutes
  4. 120 minutes
AnswerB. 20 minutes

Walking towards each other, the gap shrinks by 70 + 50 = 120 m per minute: 2,400 ÷ 120 = 20 minutes. 120 minutes divides by the difference in speed (20 m); 12 and 30 minutes are miscalculations.

Q18 | Catching-up problem

A younger brother leaves home walking at 60 m/min. Ten minutes later his older brother follows on a bicycle at 180 m/min. How many minutes after the older brother sets off does he catch up?

  1. 2.5 minutes
  2. 10 minutes
  3. 5 minutes
  4. 15 minutes
AnswerC. 5 minutes

When the older brother starts, the younger is 60 × 10 = 600 m ahead. The gap closes by 180 − 60 = 120 m per minute, so 600 ÷ 120 = 5 minutes. 2.5 minutes divides by the sum of the speeds (240 m) instead of the difference; 10 minutes confuses it with the younger brother’s head start; 15 minutes is a miscalculation.

Q19 | Train crossing a bridge

A train 160 m long travels at 20 m/s across a bridge 440 m long. How many seconds pass from when the front of the train enters the bridge until the end of the train leaves it?

  1. 22 seconds
  2. 14 seconds
  3. 30 seconds
  4. 8 seconds
AnswerC. 30 seconds

The train travels bridge length + train length = 440 + 160 = 600 m, so 600 ÷ 20 = 30 seconds. 22 seconds forgets the train’s length (440 ÷ 20); 14 seconds uses the difference; 8 seconds uses only the train’s length.

Q20 | Work problem

A can finish a job alone in 12 days, and B alone in 6 days. How many days will it take if they work together?

  1. 4 days
  2. 9 days
  3. 3 days
  4. 6 days
AnswerA. 4 days

Per day A does 1/12 and B 1/6; together 1/12 + 1/6 = 1/4, so 4 days. 9 days averages 12 and 6; 3 and 6 days add the work rates incorrectly.

Q21 | Filling a tank

Pump A alone fills a tank in 6 hours and pump B alone in 3 hours. Both pumps fill an empty tank for 1 hour, then B stops and A fills the rest alone. For how many hours does A work alone?

  1. 3 hours
  2. 2 hours
  3. 2.5 hours
  4. 4 hours
AnswerA. 3 hours

Per hour A fills 1/6 and B 1/3, so together 1/2 in the first hour. The remaining 1/2 takes A 1/2 ÷ 1/6 = 3 hours. With the tank as 6 units: A 1/h, B 2/h, 3 units in the first hour, 3 units left for A = 3 hours. The other choices misjudge the remainder or the rate.

Q22 | Work problem with a break

A can finish a job alone in 6 days and B alone in 12 days. They start together, but A takes 3 days off along the way; B works every day. How many days does the job take from start to finish?

  1. 4 days
  2. 5 days
  3. 7 days
  4. 6 days
AnswerD. 6 days

If it takes t days, B works t days and A works t − 3 days: t/12 + (t − 3)/6 = 1. Multiplying by 12: t + 2t − 6 = 12, so t = 6. 4 days ignores the break; 5 and 7 days come from wrong equations.

Q23 | Average score

The average of five tests was 72 points. What score is needed on the sixth test for the average of all six to be 75?

  1. 90
  2. 75
  3. 78
  4. 87
AnswerA. 90

Use total = average × number. Six tests need 75 × 6 = 450 points; the first five total 72 × 5 = 360; 450 − 360 = 90. 78 just adds 3 to 75; 75 and 87 also ignore totals.

Q24 | Average of groups of different sizes

Class A (20 students) averaged 60 points and class B (30 students) averaged 70 points. What is the average of both classes together?

  1. 65
  2. 66
  3. 64
  4. 67
AnswerB. 66

Total = 20 × 60 + 30 × 70 = 3,300 points for 50 students, so 66. 65 averages 60 and 70 without regard to class size; 64 and 67 are miscalculations.

Q25 | Two items, total count and price

Candies cost 50 yen each and gums 80 yen each. Someone bought 20 in total for 1,360 yen. How many candies did they buy?

  1. 8
  2. 12
  3. 10
  4. 6
AnswerA. 8

With x candies and 20 − x gums: 50x + 80(20 − x) = 1,360, so 30x = 240 and x = 8 (12 gums). Check: 400 + 960 = 1,360 yen. 12 is the number of gums; 10 and 6 do not fit.

Q26 | Age problem

A mother is now 40 and her child is 10. In how many years will the mother be exactly three times as old as the child?

  1. In 10 years
  2. In 3 years
  3. In 5 years
  4. In 20 years
AnswerC. In 5 years

In x years: 40 + x = 3(10 + x), so 2x = 10 and x = 5 (45 and 15). Remember both ages increase. In 3 years they are 43 and 13 (more than three times); in 10 years they are 50 and 20 (2.5 times); in 20 years 60 and 30 (twice).

Q27 | Contrapositive

If “When it rains, the school trip is cancelled” is true, which statement must also be true?

  1. If the trip is not cancelled, it did not rain.
  2. If the trip is cancelled, it rained.
  3. If it does not rain, the trip is not cancelled.
  4. If it does not rain, the trip is cancelled.
AnswerA. If the trip is not cancelled, it did not rain.

The contrapositive, “not cancelled → no rain”, is always true. “Cancelled → rain” is the converse and “no rain → not cancelled” is the inverse; the trip could be cancelled for another reason, so neither is guaranteed. “No rain → cancelled” cannot be concluded at all.

Q28 | Chain of reasoning

Assume (a)–(c) are true. Which statement can be concluded for certain?<br>(a) People who like reading are good at Japanese.<br>(b) People who are good at Japanese like writing essays.<br>(c) People who like arithmetic do not like writing essays.

  1. People who like writing essays like reading.
  2. People who do not like reading like arithmetic.
  3. People who like reading do not like arithmetic.
  4. People who are good at Japanese like arithmetic.
AnswerC. People who like reading do not like arithmetic.

(a) and (b) give reading → Japanese → essays. The contrapositive of (c) is essays → not arithmetic, so reading → not arithmetic. “Essays → reading” is a converse and “not reading → arithmetic” has the form of an inverse; neither is certain. “Japanese → arithmetic” contradicts the conclusion. Checking every case confirms that only “People who like reading do not like arithmetic” is certain.

Q29 | Converse and counterexample

Consider the statement “If an integer is a multiple of 4, it is even.” Which explanation is correct?

  1. Both the statement and its converse are true.
  2. The statement is true, but its converse is false; 6 is a counterexample.
  3. The statement is false; 6 is a counterexample.
  4. The statement is true, but its converse is false; 8 is a counterexample.
AnswerB. The statement is true, but its converse is false; 6 is a counterexample.

Every multiple of 4 is a multiple of 2, so the statement is true. The converse, “if even, then a multiple of 4”, is false: 6 is even but not a multiple of 4. Such an example is a counterexample. 8 is even and a multiple of 4, so it is not a counterexample.

Q30 | Truth-teller problem

Exactly one of A, B and C broke a window. They said the following, and exactly one of them is telling the truth. Who broke the window?<br>A: “B broke it.”<br>B: “I didn’t break it.”<br>C: “I didn’t break it.”

  1. A
  2. B
  3. C
  4. It cannot be determined
AnswerC. C

Test each case. If A did it, B and C are telling the truth: two people, which fails. If B did it, A and C are truthful: two again. If C did it, only B is truthful: exactly one. So C broke the window, and the answer is unique.

Q31 | Matching table

Four teachers, A–D, each teach one different subject: Japanese, arithmetic, science or music. A teaches neither Japanese nor arithmetic. B teaches science. C does not teach Japanese. D does not teach music. Which statement is certain?

  1. D teaches Japanese.
  2. A teaches science.
  3. C teaches music.
  4. D teaches arithmetic.
AnswerA. D teaches Japanese.

B teaches science, so A (not Japanese, not arithmetic) teaches music. C is not Japanese and science and music are taken, so C teaches arithmetic. Japanese is left for D (consistent with D not teaching music). Checking all 24 assignments leaves only this one.

Q32 | Ordering

Five runners, A–E, ran a race with no ties. Which statement is certain, given the following?<br>• A finished before B.<br>• C finished immediately after A.<br>• D finished after E.<br>• E was not first.<br>• B was not last.

  1. B was third.
  2. E was fourth.
  3. D was fifth.
  4. B was second.
AnswerC. D was fifth.

E is not first and finishes before D, so D is not first either; B is not first. So A is first and C, right after A, is second. B, D and E take 3rd–5th; D is after E and B is not last, so D is fifth. B and E can be 3rd/4th in either order (A-C-B-E-D or A-C-E-B-D). So only “D was fifth” is certain; B cannot be second.

Q33 | Venn diagram

In a class of 40, 25 students have a dog, 18 have a cat, and 5 have neither. How many have both a dog and a cat?

  1. 3
  2. 13
  3. 7
  4. 8
AnswerD. 8

Those with at least one pet: 40 − 5 = 35. Dog + cat − both = 35, so 25 + 18 − both = 35 and both = 8. 3 forgets the 5 with neither (25 + 18 − 40); 13 and 7 are miscalculations.

Q34 | Minimum overlap

Of 50 people, 35 own a bicycle and 40 own a smartphone. At least how many own both?

  1. 25
  2. 5
  3. 15
  4. 35
AnswerA. 25

The overlap is smallest when nobody owns neither: 35 + 40 − 50 = 25. 5 and 15 subtract the wrong numbers; 35 is the maximum possible overlap (all bicycle owners).

Q35 | Arrangements

Five people, A–E, stand in a row. In how many arrangements are A and B next to each other?

  1. 48
  2. 24
  3. 120
  4. 12
AnswerA. 48

Treat A and B as one block: 4 items can be arranged in 4 × 3 × 2 × 1 = 24 ways, and A and B can swap within the block, so 24 × 2 = 48. 24 forgets the swap; 120 is all arrangements of five people.

Q36 | Combinations

Two committee members are chosen from six people (the two roles are the same). How many ways are there?

  1. 30
  2. 12
  3. 15
  4. 36
AnswerC. 15

6 choices for the first × 5 for the second = 30, but “A and B” is the same as “B and A”, so divide by 2: 15. 30 counts ordered pairs; 12 and 36 are reasoning errors.

Q37 | Probability

Two dice (one large, one small) are thrown together. What is the probability that the total is 7?

  1. 1/11
  2. 1/12
  3. 1/6
  4. 7/36
AnswerC. 1/6

There are 6 × 6 = 36 equally likely outcomes. A total of 7 comes from (1,6), (2,5), (3,4), (4,3), (5,2), (6,1): 6 outcomes, so 6/36 = 1/6. 1/11 wrongly assumes the eleven totals 2–12 are equally likely; 1/12 and 7/36 are counting errors.

Q38 | Days of the week

In a certain year, 1 April was a Wednesday. What day of the week was 1 June in the same year?

  1. Monday
  2. Wednesday
  3. Sunday
  4. Tuesday
AnswerA. Monday

April has 30 days and May 31, so 1 June is 61 days after 1 April. 61 ÷ 7 = 8 remainder 5, so move 5 days on from Wednesday: Monday. Wednesday ignores the remainder; Sunday and Tuesday miscount the days (April and May have the same lengths every year).

Q39 | Amount per person
Five elementary schools in a fictional city: pupils and library loans (FY2025)
SchoolPupilsBooks lent per year
East42012,600
West2809,800
South65016,250
North36011,520
Central51014,280

Among the five schools in the table, which has the most books lent per pupil per year?

  1. South
  2. West
  3. North
  4. Central
AnswerB. West

Books per pupil = books lent ÷ pupils: East 30, West 35, South 25, North 32, Central 28. West is highest. South lends the most books in total but also has the most pupils, so it is lowest per pupil.

Q40 | What can be said for certain (table)
Five elementary schools in a fictional city: pupils and library loans (FY2025)
SchoolPupilsBooks lent per year
East42012,600
West2809,800
South65016,250
North36011,520
Central51014,280

Which statement can be concluded for certain from the table?

  1. South, which lends the most books, also lends the most per pupil.
  2. East and Central together lend more than twice as many books as South.
  3. The simple average of the five schools’ books per pupil is more than 30.
  4. North lends 4 more books per pupil than Central.
AnswerD. North lends 4 more books per pupil than Central.

North: 11,520 ÷ 360 = 32; Central: 14,280 ÷ 510 = 28; the difference is 4, so this is true. South is lowest at 25 per pupil. East + Central = 26,880, short of twice South (32,500). The simple average is (30 + 35 + 25 + 32 + 28) ÷ 5 = exactly 30, not more.

Q41 | Overall amount per person
Five elementary schools in a fictional city: pupils and library loans (FY2025)
SchoolPupilsBooks lent per year
East42012,600
West2809,800
South65016,250
North36011,520
Central51014,280

For the five schools as a whole, which is closest to the number of books lent per pupil (total books lent ÷ total pupils)?

  1. About 27.5
  2. About 30.0
  3. About 29.0
  4. About 31.0
AnswerC. About 29.0

Total books = 64,450 and total pupils = 2,220, so 64,450 ÷ 2,220 ≈ 29.03. About 30.0 is the simple average of the five schools and ignores the weight of South (25 per pupil), which has the most pupils.

Q42 | Share of the total
Population of a fictional town by age group (people)
Age group20152025
0-143,2002,400
15-6414,80012,950
65 and over6,0007,650
Total24,00023,000

In the table, which is closest to the share of people aged 65 and over in the 2025 total population?

  1. About 25%
  2. About 28%
  3. About 33%
  4. About 38%
AnswerC. About 33%

7,650 ÷ 23,000 ≈ 0.333, about 33% (one third of 23,000 is about 7,667). About 25% is the 2015 share (6,000 ÷ 24,000); about 28% confuses it with the growth rate (27.5%).

Q43 | Rates of increase and decrease
Population of a fictional town by age group (people)
Age group20152025
0-143,2002,400
15-6414,80012,950
65 and over6,0007,650
Total24,00023,000

Which statement can be concluded for certain from the table?

  1. The increase in people aged 65 and over is smaller than the decrease in the 0–14 group.
  2. The rate of decrease of the 0–14 group is twice that of the 15–64 group.
  3. The total population fell by more than 5% from 2015 to 2025.
  4. The share of the 15–64 group is over 60% in both 2015 and 2025.
AnswerB. The rate of decrease of the 0–14 group is twice that of the 15–64 group.

0–14: 800 ÷ 3,200 = a 25% fall; 15–64: 1,850 ÷ 14,800 = a 12.5% fall, exactly half. The 65+ group grew by 1,650, more than the 800 fall in the 0–14 group. The total fell by 1,000 ÷ 24,000 ≈ 4.2%, not over 5%. The 15–64 share was about 61.7% in 2015 but about 56.3% in 2025.

Q44 | Percentage points vs percent
Population of a fictional town by age group (people)
Age group20152025
0-143,2002,400
15-6414,80012,950
65 and over6,0007,650
Total24,00023,000

How did the share of the 0–14 age group in the total population change from 2015 to 2025? Choose the closest.

  1. It fell by about 25 percentage points.
  2. It fell by about 2.9 percentage points.
  3. It fell by about 0.8 percentage points.
  4. It fell by about 8.0 percentage points.
AnswerB. It fell by about 2.9 percentage points.

The share was 3,200 ÷ 24,000 ≈ 13.3% in 2015 and 2,400 ÷ 23,000 ≈ 10.4% in 2025, a difference of about 2.9 points. “25” is the rate of decrease of the group itself (25%), not a difference in shares. 0.8 and 8.0 confuse the head count (800) with the share.

Q45 | Month-on-month growth rate
(thousand)051015202512Apr15May18Jun14Jul20Aug24Sep
Monthly page views of a fictional learning site (2025, thousands): Apr 12, May 15, Jun 18, Jul 14, Aug 20, Sep 24

In the chart, which month has the largest rate of increase from the previous month?

  1. May
  2. August
  3. June
  4. September
AnswerB. August

Growth from the previous month: May 25% (3 ÷ 12), June 20% (3 ÷ 15), August about 42.9% (6 ÷ 14), September 20% (4 ÷ 20); July fell. August is the largest. September looks large in absolute terms (4 thousand), but its base (20 thousand) is also large.

Q46 | Comparing with the average
(thousand)051015202512Apr15May18Jun14Jul20Aug24Sep
Monthly page views of a fictional learning site (2025, thousands): Apr 12, May 15, Jun 18, Jul 14, Aug 20, Sep 24

In how many of the six months were page views above the six-month average?

  1. 2
  2. 4
  3. 5
  4. 3
AnswerD. 3

The total is 12 + 15 + 18 + 14 + 20 + 24 = 103 thousand, an average of about 17.2 thousand. June (18), August (20) and September (24) are above it: 3 months. May (15) is below.

Q47 | What can be said for certain (chart)
(thousand)051015202512Apr15May18Jun14Jul20Aug24Sep
Monthly page views of a fictional learning site (2025, thousands): Apr 12, May 15, Jun 18, Jul 14, Aug 20, Sep 24

Which statement can be concluded for certain from the chart?

  1. Total page views from April to September are under 100 thousand.
  2. September’s page views are three times April’s.
  3. The rate of decrease from June to July is less than 20%.
  4. Page views fell from the previous month only once in the six months.
AnswerD. Page views fell from the previous month only once in the six months.

Only July (18 → 14) fell from the previous month, so this is true. The total is 103 thousand, over 100 thousand. September (24) is twice April (12). The June–July decrease is 4 ÷ 18 ≈ 22.2%, more than 20%.

Q48 | From shares to actual numbers
WalkBicycleBus2015 (500 students)60%30%10%2025 (400 students)55%25%20%
How students get to a fictional junior high school. 2015 (500 students): walk 60%, bicycle 30%, bus 10%; 2025 (400 students): walk 55%, bicycle 25%, bus 20%

In the chart, how did the number of students who cycle to school change from 2015 to 2025?

  1. It fell by 5.
  2. It fell by 50.
  3. It fell by 20.
  4. It did not change.
AnswerB. It fell by 50.

In actual numbers: 2015: 500 × 0.30 = 150; 2025: 400 × 0.25 = 100, a fall of 50. “5” confuses the 5-point difference in share with a head count. Because the totals differ, shares alone cannot compare numbers of students.

Q49 | Reading a band chart
WalkBicycleBus2015 (500 students)60%30%10%2025 (400 students)55%25%20%
How students get to a fictional junior high school. 2015 (500 students): walk 60%, bicycle 30%, bus 10%; 2025 (400 students): walk 55%, bicycle 25%, bus 20%

Which statement can be concluded for certain from the chart?

  1. The number of bus students doubled from 2015.
  2. The number of students who walk increased from 2015.
  3. The bus share doubled, but the number of bus students rose by 30.
  4. Because the cycling share fell by 5 points, the number of cyclists also fell by 5%.
AnswerC. The bus share doubled, but the number of bus students rose by 30.

Bus: 10% → 20%, so the share doubled; students: 500 × 0.1 = 50 → 400 × 0.2 = 80, up 30. This is true. The number grew 1.6 times, not 2. Walkers fell from 300 to 220. Cyclists fell from 150 to 100, about 33%. A point change is not the same as a rate of change in numbers.

Q50 | Reading an index
Visitor index of libraries A and B in a fictional city (each library’s own 2020 visitors = 100)
Library202020232024
A100130120
B100115138

The table shows visitors to libraries A and B as an index, with each library’s own 2020 visitors set to 100. Which statement can be concluded for certain?

  1. In 2024, library B had more visitors than library A.
  2. Library A’s visitors fell by 10% from 2023 to 2024.
  3. From 2020 to 2024, library B gained more visitors than library A.
  4. Library B’s visitors in 2024 were 1.2 times those in 2023.
AnswerD. Library B’s visitors in 2024 were 1.2 times those in 2023.

Within one library, the index can be compared: B rose 138 ÷ 115 = 1.2 times, so this is true. A fell 120 ÷ 130 ≈ 0.923, about 7.7% (a 10-point drop is not a 10% drop). Since the two libraries’ 2020 visitor numbers (the bases) are unknown, their visitor numbers and increases cannot be compared.

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